Distance from Lexington Park to Bad Sooden-Allendorf
The shortest distance (air line) between Lexington Park and Bad Sooden-Allendorf is 4,082.69 mi (6,570.46 km).
How far is Lexington Park from Bad Sooden-Allendorf
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 21:51 (22.02.2025)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 03:51 (23.02.2025)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 4,082.69 miles which is equal to 6,570.46 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany