Distance from Lexington Park to Boguszow-Gorce
The shortest distance (air line) between Lexington Park and Boguszow-Gorce is 4,340.97 mi (6,986.12 km).
How far is Lexington Park from Boguszow-Gorce
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 01:55 (12.03.2025)
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 07:55 (12.03.2025)
The calculated flying distance from Boguszow-Gorce to Boguszow-Gorce is 4,340.97 miles which is equal to 6,986.12 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Boguszow-Gorce, Wałbrzyski, Poland