Distance from Lexington Park to Cervignano del Friuli
The shortest distance (air line) between Lexington Park and Cervignano del Friuli is 4,387.58 mi (7,061.13 km).
How far is Lexington Park from Cervignano del Friuli
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 14:06 (01.03.2025)
Cervignano del Friuli is located in Udine, Italy within 45° 49' 23.16" N 13° 20' 6" E (45.8231, 13.3350) coordinates. The local time in Cervignano del Friuli is 20:06 (01.03.2025)
The calculated flying distance from Cervignano del Friuli to Cervignano del Friuli is 4,387.58 miles which is equal to 7,061.13 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Cervignano del Friuli, Udine, Italy