Distance from Lexington Park to Diepenbeek
The shortest distance (air line) between Lexington Park and Diepenbeek is 3,909.93 mi (6,292.42 km).
How far is Lexington Park from Diepenbeek
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 10:26 (23.01.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 16:26 (23.01.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,909.93 miles which is equal to 6,292.42 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Diepenbeek, Arr. Hasselt, Belgium