Distance from Lexington Park to Oud-Turnhout
The shortest distance (air line) between Lexington Park and Oud-Turnhout is 3,882.17 mi (6,247.75 km).
How far is Lexington Park from Oud-Turnhout
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 20:50 (23.01.2025)
Oud-Turnhout is located in Arr. Turnhout, Belgium within 51° 19' 0.12" N 4° 58' 59.88" E (51.3167, 4.9833) coordinates. The local time in Oud-Turnhout is 02:50 (24.01.2025)
The calculated flying distance from Oud-Turnhout to Oud-Turnhout is 3,882.17 miles which is equal to 6,247.75 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Oud-Turnhout, Arr. Turnhout, Belgium