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      Distance from Lexington Park to Saint-Andre-les-Vergers

      The shortest distance (air line) between Lexington Park and Saint-Andre-les-Vergers is 3,920.49 mi (6,309.42 km).

      How far is Lexington Park from Saint-Andre-les-Vergers

      Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 16:47 (13.02.2025)

      Saint-Andre-les-Vergers is located in Aube, France within 48° 16' 46.92" N 4° 3' 14.04" E (48.2797, 4.0539) coordinates. The local time in Saint-Andre-les-Vergers is 22:47 (13.02.2025)

      The calculated flying distance from Saint-Andre-les-Vergers to Saint-Andre-les-Vergers is 3,920.49 miles which is equal to 6,309.42 km.

      Lexington Park, Maryland, United States

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      Saint-Andre-les-Vergers, Aube, France

      Related Distances to Saint-Andre-les-Vergers