Distance from Lexington Park to Saint-Avertin
The shortest distance (air line) between Lexington Park and Saint-Avertin is 3,799.95 mi (6,115.43 km).
How far is Lexington Park from Saint-Avertin
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 17:27 (13.02.2025)
Saint-Avertin is located in Indre-et-Loire, France within 47° 22' 0.12" N 0° 43' 36.12" E (47.3667, 0.7267) coordinates. The local time in Saint-Avertin is 23:27 (13.02.2025)
The calculated flying distance from Saint-Avertin to Saint-Avertin is 3,799.95 miles which is equal to 6,115.43 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Saint-Avertin, Indre-et-Loire, France