Distance from Lexington Park to Saint-Genis-Pouilly
The shortest distance (air line) between Lexington Park and Saint-Genis-Pouilly is 4,060.88 mi (6,535.35 km).
How far is Lexington Park from Saint-Genis-Pouilly
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 17:12 (13.02.2025)
Saint-Genis-Pouilly is located in Ain, France within 46° 14' 35.88" N 6° 1' 17.04" E (46.2433, 6.0214) coordinates. The local time in Saint-Genis-Pouilly is 23:12 (13.02.2025)
The calculated flying distance from Saint-Genis-Pouilly to Saint-Genis-Pouilly is 4,060.88 miles which is equal to 6,535.35 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Saint-Genis-Pouilly, Ain, France