Distance from Lexington Park to Sajoszentpeter
The shortest distance (air line) between Lexington Park and Sajoszentpeter is 4,604.64 mi (7,410.45 km).
How far is Lexington Park from Sajoszentpeter
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 07:35 (28.02.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 13:35 (28.02.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 4,604.64 miles which is equal to 7,410.45 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary