Distance from Lexington Park to San Bonifacio
The shortest distance (air line) between Lexington Park and San Bonifacio is 4,314.00 mi (6,942.71 km).
How far is Lexington Park from San Bonifacio
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 23:37 (04.03.2025)
San Bonifacio is located in Verona, Italy within 45° 23' 60" N 11° 16' 59.88" E (45.4000, 11.2833) coordinates. The local time in San Bonifacio is 05:37 (05.03.2025)
The calculated flying distance from San Bonifacio to San Bonifacio is 4,314.00 miles which is equal to 6,942.71 km.
Lexington Park, Maryland, United States