Distance from Lexington Park to San Cesareo
The shortest distance (air line) between Lexington Park and San Cesareo is 4,500.12 mi (7,242.24 km).
How far is Lexington Park from San Cesareo
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 23:33 (04.03.2025)
San Cesareo is located in Roma, Italy within 41° 49' 0.12" N 12° 48' 0" E (41.8167, 12.8000) coordinates. The local time in San Cesareo is 05:33 (05.03.2025)
The calculated flying distance from San Cesareo to San Cesareo is 4,500.12 miles which is equal to 7,242.24 km.
Lexington Park, Maryland, United States