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      Distance from Lexington Park to San Ferdinando di Puglia

      The shortest distance (air line) between Lexington Park and San Ferdinando di Puglia is 4,663.29 mi (7,504.85 km).

      How far is Lexington Park from San Ferdinando di Puglia

      Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 23:44 (04.03.2025)

      San Ferdinando di Puglia is located in Barletta-Andria-Trani, Italy within 41° 17' 60" N 16° 4' 0.12" E (41.3000, 16.0667) coordinates. The local time in San Ferdinando di Puglia is 05:44 (05.03.2025)

      The calculated flying distance from San Ferdinando di Puglia to San Ferdinando di Puglia is 4,663.29 miles which is equal to 7,504.85 km.

      Lexington Park, Maryland, United States

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      San Ferdinando di Puglia, Barletta-Andria-Trani, Italy

      Related Distances to San Ferdinando di Puglia