Distance from Lexington Park to San Gavino Monreale
The shortest distance (air line) between Lexington Park and San Gavino Monreale is 4,394.74 mi (7,072.66 km).
How far is Lexington Park from San Gavino Monreale
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 23:35 (04.03.2025)
San Gavino Monreale is located in Sud Sardegna, Italy within 39° 32' 59.64" N 8° 47' 29.76" E (39.5499, 8.7916) coordinates. The local time in San Gavino Monreale is 05:35 (05.03.2025)
The calculated flying distance from San Gavino Monreale to San Gavino Monreale is 4,394.74 miles which is equal to 7,072.66 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Gavino Monreale, Sud Sardegna, Italy