Distance from Lexington Park to San Gennaro Vesuviano
The shortest distance (air line) between Lexington Park and San Gennaro Vesuviano is 4,610.93 mi (7,420.58 km).
How far is Lexington Park from San Gennaro Vesuviano
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 23:28 (04.03.2025)
San Gennaro Vesuviano is located in Napoli, Italy within 40° 52' 0.12" N 14° 31' 59.88" E (40.8667, 14.5333) coordinates. The local time in San Gennaro Vesuviano is 05:28 (05.03.2025)
The calculated flying distance from San Gennaro Vesuviano to San Gennaro Vesuviano is 4,610.93 miles which is equal to 7,420.58 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Gennaro Vesuviano, Napoli, Italy