Distance from Lexington Park to San Giorgio del Sannio
The shortest distance (air line) between Lexington Park and San Giorgio del Sannio is 4,617.86 mi (7,431.73 km).
How far is Lexington Park from San Giorgio del Sannio
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 23:14 (04.03.2025)
San Giorgio del Sannio is located in Benevento, Italy within 41° 4' 0.12" N 14° 50' 60" E (41.0667, 14.8500) coordinates. The local time in San Giorgio del Sannio is 05:14 (05.03.2025)
The calculated flying distance from San Giorgio del Sannio to San Giorgio del Sannio is 4,617.86 miles which is equal to 7,431.73 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Giorgio del Sannio, Benevento, Italy