Distance from Lexington Park to San Giovanni Rotondo
The shortest distance (air line) between Lexington Park and San Giovanni Rotondo is 4,634.09 mi (7,457.84 km).
How far is Lexington Park from San Giovanni Rotondo
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 15:03 (05.03.2025)
San Giovanni Rotondo is located in Foggia, Italy within 41° 42' 0" N 15° 43' 59.88" E (41.7000, 15.7333) coordinates. The local time in San Giovanni Rotondo is 21:03 (05.03.2025)
The calculated flying distance from San Giovanni Rotondo to San Giovanni Rotondo is 4,634.09 miles which is equal to 7,457.84 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Giovanni Rotondo, Foggia, Italy