Distance from Lexington Park to San Giovanni in Fiore
The shortest distance (air line) between Lexington Park and San Giovanni in Fiore is 4,766.81 mi (7,671.45 km).
How far is Lexington Park from San Giovanni in Fiore
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 23:29 (04.03.2025)
San Giovanni in Fiore is located in Cosenza, Italy within 39° 15' 51.12" N 16° 42' 1.08" E (39.2642, 16.7003) coordinates. The local time in San Giovanni in Fiore is 05:29 (05.03.2025)
The calculated flying distance from San Giovanni in Fiore to San Giovanni in Fiore is 4,766.81 miles which is equal to 7,671.45 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Giovanni in Fiore, Cosenza, Italy