Distance from Lexington Park to San Giuliano Milanese
The shortest distance (air line) between Lexington Park and San Giuliano Milanese is 4,227.69 mi (6,803.82 km).
How far is Lexington Park from San Giuliano Milanese
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 14:57 (05.03.2025)
San Giuliano Milanese is located in Milano, Italy within 45° 23' 60" N 9° 16' 59.88" E (45.4000, 9.2833) coordinates. The local time in San Giuliano Milanese is 20:57 (05.03.2025)
The calculated flying distance from San Giuliano Milanese to San Giuliano Milanese is 4,227.69 miles which is equal to 6,803.82 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Giuliano Milanese, Milano, Italy