Distance from Lexington Park to San Giuliano Terme
The shortest distance (air line) between Lexington Park and San Giuliano Terme is 4,330.29 mi (6,968.93 km).
How far is Lexington Park from San Giuliano Terme
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 15:09 (05.03.2025)
San Giuliano Terme is located in Pisa, Italy within 43° 45' 45" N 10° 26' 29.04" E (43.7625, 10.4414) coordinates. The local time in San Giuliano Terme is 21:09 (05.03.2025)
The calculated flying distance from San Giuliano Terme to San Giuliano Terme is 4,330.29 miles which is equal to 6,968.93 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Giuliano Terme, Pisa, Italy