Distance from Lexington Park to San Giustino
The shortest distance (air line) between Lexington Park and San Giustino is 4,413.80 mi (7,103.33 km).
How far is Lexington Park from San Giustino
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 14:59 (05.03.2025)
San Giustino is located in Perugia, Italy within 43° 32' 60" N 12° 10' 59.88" E (43.5500, 12.1833) coordinates. The local time in San Giustino is 20:59 (05.03.2025)
The calculated flying distance from San Giustino to San Giustino is 4,413.80 miles which is equal to 7,103.33 km.
Lexington Park, Maryland, United States