Distance from Lexington Park to San Lazzaro di Savena
The shortest distance (air line) between Lexington Park and San Lazzaro di Savena is 4,349.34 mi (6,999.59 km).
How far is Lexington Park from San Lazzaro di Savena
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 15:02 (05.03.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 21:02 (05.03.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,349.34 miles which is equal to 6,999.59 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
San Lazzaro di Savena, Bologna, Italy