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      Distance from Lexington Park to San Martino Buon Albergo

      The shortest distance (air line) between Lexington Park and San Martino Buon Albergo is 4,305.59 mi (6,929.17 km).

      How far is Lexington Park from San Martino Buon Albergo

      Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 15:16 (05.03.2025)

      San Martino Buon Albergo is located in Verona, Italy within 45° 25' 0.12" N 11° 5' 60" E (45.4167, 11.1000) coordinates. The local time in San Martino Buon Albergo is 21:16 (05.03.2025)

      The calculated flying distance from San Martino Buon Albergo to San Martino Buon Albergo is 4,305.59 miles which is equal to 6,929.17 km.

      Lexington Park, Maryland, United States

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      San Martino Buon Albergo, Verona, Italy

      Related Distances to San Martino Buon Albergo