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      Distance from Lexington Park to San Pancrazio Salentino

      The shortest distance (air line) between Lexington Park and San Pancrazio Salentino is 4,773.94 mi (7,682.91 km).

      How far is Lexington Park from San Pancrazio Salentino

      Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 14:50 (05.03.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 20:50 (05.03.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 4,773.94 miles which is equal to 7,682.91 km.

      Lexington Park, Maryland, United States

      Related Distances from Lexington Park

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      Lexington Park to Phoenix (Arizona)2,008.21 mi (3,231.91 km)
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      Lexington Park to Portland (Oregon)2,394.79 mi (3,854.04 km)
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      Lexington Park to Washington (District of Columbia)54.68 mi (88.00 km)
      Lexington Park to Brooklyn (New York)212.40 mi (341.83 km)
      Lexington Park to New York (New York)215.58 mi (346.95 km)
      Lexington Park to Queens (New York)222.79 mi (358.55 km)
      Lexington Park to Boston (Massachusetts)398.15 mi (640.75 km)
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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino