Distance from Lexington Park to Santa Croce Camerina
The shortest distance (air line) between Lexington Park and Santa Croce Camerina is 4,758.35 mi (7,657.83 km).
How far is Lexington Park from Santa Croce Camerina
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 14:54 (05.03.2025)
Santa Croce Camerina is located in Ragusa, Italy within 36° 49' 37.92" N 14° 31' 26.04" E (36.8272, 14.5239) coordinates. The local time in Santa Croce Camerina is 20:54 (05.03.2025)
The calculated flying distance from Santa Croce Camerina to Santa Croce Camerina is 4,758.35 miles which is equal to 7,657.83 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Santa Croce Camerina, Ragusa, Italy