Distance from Lexington Park to Scherpenheuvel
The shortest distance (air line) between Lexington Park and Scherpenheuvel is 3,889.31 mi (6,259.24 km).
How far is Lexington Park from Scherpenheuvel
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 00:13 (03.02.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 06:13 (03.02.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 3,889.31 miles which is equal to 6,259.24 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Scherpenheuvel, Arr. Leuven, Belgium