Distance from Lexington Park to Sint-Amandsberg
The shortest distance (air line) between Lexington Park and Sint-Amandsberg is 3,838.49 mi (6,177.45 km).
How far is Lexington Park from Sint-Amandsberg
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 20:53 (23.01.2025)
Sint-Amandsberg is located in Arr. Gent, Belgium within 51° 3' 14.04" N 3° 44' 57.12" E (51.0539, 3.7492) coordinates. The local time in Sint-Amandsberg is 02:53 (24.01.2025)
The calculated flying distance from Sint-Amandsberg to Sint-Amandsberg is 3,838.49 miles which is equal to 6,177.45 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Sint-Amandsberg, Arr. Gent, Belgium