Distance from Lexington Park to Sint Anthonis
The shortest distance (air line) between Lexington Park and Sint Anthonis is 3,910.57 mi (6,293.46 km).
How far is Lexington Park from Sint Anthonis
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 10:15 (10.03.2025)
Sint Anthonis is located in Noordoost-Noord-Brabant, Netherlands within 51° 37' 32.88" N 5° 52' 51.96" E (51.6258, 5.8811) coordinates. The local time in Sint Anthonis is 16:15 (10.03.2025)
The calculated flying distance from Sint Anthonis to Sint Anthonis is 3,910.57 miles which is equal to 6,293.46 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Sint Anthonis, Noordoost-Noord-Brabant, Netherlands