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      Distance from Lexington Park to Sint-Genesius-Rode

      The shortest distance (air line) between Lexington Park and Sint-Genesius-Rode is 3,870.34 mi (6,228.71 km).

      How far is Lexington Park from Sint-Genesius-Rode

      Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 20:25 (23.01.2025)

      Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 02:25 (24.01.2025)

      The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 3,870.34 miles which is equal to 6,228.71 km.

      Lexington Park, Maryland, United States

      Related Distances from Lexington Park

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      Lexington Park to Portland (Oregon)2,394.79 mi (3,854.04 km)
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      Lexington Park to Washington (District of Columbia)54.68 mi (88.00 km)
      Lexington Park to Brooklyn (New York)212.40 mi (341.83 km)
      Lexington Park to New York (New York)215.58 mi (346.95 km)
      Lexington Park to Queens (New York)222.79 mi (358.55 km)
      Lexington Park to Boston (Massachusetts)398.15 mi (640.75 km)
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      Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Genesius-Rode