Distance from Lexington Park to Sint-Katelijne-Waver
The shortest distance (air line) between Lexington Park and Sint-Katelijne-Waver is 3,870.08 mi (6,228.29 km).
How far is Lexington Park from Sint-Katelijne-Waver
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 01:07 (24.01.2025)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 07:07 (24.01.2025)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 3,870.08 miles which is equal to 6,228.29 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Sint-Katelijne-Waver, Arr. Mechelen, Belgium