Distance from Lexington Park to Sint-Kruis
The shortest distance (air line) between Lexington Park and Sint-Kruis is 3,814.42 mi (6,138.71 km).
How far is Lexington Park from Sint-Kruis
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 00:51 (24.01.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 06:51 (24.01.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 3,814.42 miles which is equal to 6,138.71 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Sint-Kruis, Arr. Brugge, Belgium