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      Distance from Lexington Park to Sint-Pieters-Leeuw

      The shortest distance (air line) between Lexington Park and Sint-Pieters-Leeuw is 3,865.46 mi (6,220.86 km).

      How far is Lexington Park from Sint-Pieters-Leeuw

      Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 01:05 (24.01.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 07:05 (24.01.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 3,865.46 miles which is equal to 6,220.86 km.

      Lexington Park, Maryland, United States

      Related Distances from Lexington Park

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      Lexington Park to Washington (District of Columbia)54.68 mi (88.00 km)
      Lexington Park to Brooklyn (New York)212.40 mi (341.83 km)
      Lexington Park to New York (New York)215.58 mi (346.95 km)
      Lexington Park to Queens (New York)222.79 mi (358.55 km)
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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw