Distance from Lexington Park to Sokolow Podlaski
The shortest distance (air line) between Lexington Park and Sokolow Podlaski is 4,510.69 mi (7,259.25 km).
How far is Lexington Park from Sokolow Podlaski
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 11:16 (14.03.2025)
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 17:16 (14.03.2025)
The calculated flying distance from Sokolow Podlaski to Sokolow Podlaski is 4,510.69 miles which is equal to 7,259.25 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Sokolow Podlaski, Siedlecki, Poland