Distance from Lexington Park to Sveti Ivan Zelina
The shortest distance (air line) between Lexington Park and Sveti Ivan Zelina is 4,504.74 mi (7,249.67 km).
How far is Lexington Park from Sveti Ivan Zelina
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 18:42 (24.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 00:42 (25.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,504.74 miles which is equal to 7,249.67 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Sveti Ivan Zelina, Zagrebačka županija, Croatia