Distance from Lexington Park to Swinoujscie
The shortest distance (air line) between Lexington Park and Swinoujscie is 4,169.46 mi (6,710.10 km).
How far is Lexington Park from Swinoujscie
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 06:58 (13.03.2025)
Swinoujscie is located in Szczeciński, Poland within 53° 55' 0.12" N 14° 15' 0" E (53.9167, 14.2500) coordinates. The local time in Swinoujscie is 12:58 (13.03.2025)
The calculated flying distance from Swinoujscie to Swinoujscie is 4,169.46 miles which is equal to 6,710.10 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Swinoujscie, Szczeciński, Poland