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      Distance from Lexington Park to Villeneuve-les-Avignon

      The shortest distance (air line) between Lexington Park and Villeneuve-les-Avignon is 4,072.43 mi (6,553.94 km).

      How far is Lexington Park from Villeneuve-les-Avignon

      Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 14:07 (21.02.2025)

      Villeneuve-les-Avignon is located in Gard, France within 43° 57' 59.04" N 4° 47' 44.88" E (43.9664, 4.7958) coordinates. The local time in Villeneuve-les-Avignon is 20:07 (21.02.2025)

      The calculated flying distance from Villeneuve-les-Avignon to Villeneuve-les-Avignon is 4,072.43 miles which is equal to 6,553.94 km.

      Lexington Park, Maryland, United States

      Related Distances from Lexington Park

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      Lexington Park to Washington (District of Columbia)54.68 mi (88.00 km)
      Lexington Park to Brooklyn (New York)212.40 mi (341.83 km)
      Lexington Park to New York (New York)215.58 mi (346.95 km)
      Lexington Park to Queens (New York)222.79 mi (358.55 km)
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      Villeneuve-les-Avignon, Gard, France

      Related Distances to Villeneuve-les-Avignon