Distance from Lidzbark Warminski to Deerfield Beach
The shortest distance (air line) between Lidzbark Warminski and Deerfield Beach is 5,171.46 mi (8,322.66 km).
How far is Lidzbark Warminski from Deerfield Beach
Lidzbark Warminski is located in Olsztyński, Poland within 54° 7' 0.12" N 20° 34' 59.88" E (54.1167, 20.5833) coordinates. The local time in Lidzbark Warminski is 05:12 (08.10.2025)
Deerfield Beach is located in Florida, United States within 26° 18' 18" N -81° 52' 20.28" W (26.3050, -80.1277) coordinates. The local time in Deerfield Beach is 23:12 (07.10.2025)
The calculated flying distance from Deerfield Beach to Deerfield Beach is 5,171.46 miles which is equal to 8,322.66 km.
Lidzbark Warminski, Olsztyński, Poland
Related Distances from Lidzbark Warminski
Deerfield Beach, Florida, United States