Distance from Lompoc to Cesky Tesin
The shortest distance (air line) between Lompoc and Cesky Tesin is 6,090.38 mi (9,801.52 km).
How far is Lompoc from Cesky Tesin
Lompoc is located in California, United States within 34° 39' 42.48" N -121° 31' 42.96" W (34.6618, -120.4714) coordinates. The local time in Lompoc is 01:49 (24.04.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 10:49 (24.04.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 6,090.38 miles which is equal to 9,801.52 km.
Lompoc, California, United States
Related Distances from Lompoc
Cesky Tesin, Moravskoslezský kraj, Czechia