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      Distance from Lompoc to Chateauneuf-les-Martigues

      The shortest distance (air line) between Lompoc and Chateauneuf-les-Martigues is 6,050.67 mi (9,737.61 km).

      How far is Lompoc from Chateauneuf-les-Martigues

      Lompoc is located in California, United States within 34° 39' 42.48" N -121° 31' 42.96" W (34.6618, -120.4714) coordinates. The local time in Lompoc is 18:50 (28.04.2025)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 03:50 (29.04.2025)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 6,050.67 miles which is equal to 9,737.61 km.

      Lompoc, California, United States

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      Lompoc to Philadelphia (Pennsylvania)2,490.90 mi (4,008.72 km)
      Lompoc to Brooklyn (New York)2,548.20 mi (4,100.93 km)
      Lompoc to New York (New York)2,549.17 mi (4,102.49 km)
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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues