Distance from Lovejoy to Sendenhorst
The shortest distance (air line) between Lovejoy and Sendenhorst is 4,528.42 mi (7,287.78 km).
How far is Lovejoy from Sendenhorst
Lovejoy is located in Georgia, United States within 33° 26' 33.36" N -85° 40' 56.28" W (33.4426, -84.3177) coordinates. The local time in Lovejoy is 13:50 (11.03.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 19:50 (11.03.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 4,528.42 miles which is equal to 7,287.78 km.
Lovejoy, Georgia, United States
Related Distances from Lovejoy
Sendenhorst, Warendorf, Germany