Distance from Lovejoy to Sint-Genesius-Rode
The shortest distance (air line) between Lovejoy and Sint-Genesius-Rode is 4,418.99 mi (7,111.67 km).
How far is Lovejoy from Sint-Genesius-Rode
Lovejoy is located in Georgia, United States within 33° 26' 33.36" N -85° 40' 56.28" W (33.4426, -84.3177) coordinates. The local time in Lovejoy is 07:10 (03.02.2025)
Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 13:10 (03.02.2025)
The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 4,418.99 miles which is equal to 7,111.67 km.
Lovejoy, Georgia, United States
Related Distances from Lovejoy
Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium