Distance from Lovejoy to Sint-Kruis
The shortest distance (air line) between Lovejoy and Sint-Kruis is 4,362.83 mi (7,021.30 km).
How far is Lovejoy from Sint-Kruis
Lovejoy is located in Georgia, United States within 33° 26' 33.36" N -85° 40' 56.28" W (33.4426, -84.3177) coordinates. The local time in Lovejoy is 08:14 (03.02.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 14:14 (03.02.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 4,362.83 miles which is equal to 7,021.30 km.
Lovejoy, Georgia, United States
Related Distances from Lovejoy
Sint-Kruis, Arr. Brugge, Belgium