Distance from Lukovica to Jefferson Hills
The shortest distance (air line) between Lukovica and Jefferson Hills is 4,485.27 mi (7,218.35 km).
How far is Lukovica from Jefferson Hills
Lukovica is located in Osrednjeslovenska, Slovenia within 46° 10' 6.96" N 14° 41' 21.12" E (46.1686, 14.6892) coordinates. The local time in Lukovica is 01:42 (17.12.2025)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 19:42 (16.12.2025)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 4,485.27 miles which is equal to 7,218.35 km.
Lukovica, Osrednjeslovenska, Slovenia
Related Distances from Lukovica
Jefferson Hills, Pennsylvania, United States