Distance from Lukovica to Johnstown
The shortest distance (air line) between Lukovica and Johnstown is 4,442.96 mi (7,150.25 km).
How far is Lukovica from Johnstown
Lukovica is located in Osrednjeslovenska, Slovenia within 46° 10' 6.96" N 14° 41' 21.12" E (46.1686, 14.6892) coordinates. The local time in Lukovica is 00:44 (18.12.2025)
Johnstown is located in Pennsylvania, United States within 40° 19' 33.6" N -79° 4' 50.16" W (40.3260, -78.9194) coordinates. The local time in Johnstown is 18:44 (17.12.2025)
The calculated flying distance from Johnstown to Johnstown is 4,442.96 miles which is equal to 7,150.25 km.
Lukovica, Osrednjeslovenska, Slovenia
Related Distances from Lukovica
Johnstown, Pennsylvania, United States