Distance from Luxembourg to Aleksandrow Kujawski
The shortest distance (air line) between Luxembourg and Aleksandrow Kujawski is 587.30 mi (945.17 km).
How far is Luxembourg from Aleksandrow Kujawski
Luxembourg is located in Luxembourg, Luxembourg within 49° 36' 42.12" N 6° 7' 54.84" E (49.6117, 6.1319) coordinates. The local time in Luxembourg is 17:20 (14.02.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 17:20 (14.02.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 587.30 miles which is equal to 945.17 km.
Luxembourg, Luxembourg, Luxembourg
Related Distances from Luxembourg
| Cities | Distance |
|---|---|
| Luxembourg to Capellen | 6.75 mi (10.87 km) |
| Luxembourg to Dudelange | 9.14 mi (14.70 km) |
| Luxembourg to Mersch | 9.66 mi (15.55 km) |
| Luxembourg to Esch-sur-Alzette | 10.44 mi (16.79 km) |
| Luxembourg to Remich | 11.50 mi (18.51 km) |
| Luxembourg to Differdange | 12.41 mi (19.98 km) |
| Luxembourg to Grevenmacher | 14.65 mi (23.58 km) |
| Luxembourg to Redange-sur-Attert | 15.17 mi (24.41 km) |
| Luxembourg to Diekirch | 17.75 mi (28.57 km) |
| Luxembourg to Echternach | 18.94 mi (30.48 km) |
| Luxembourg to Vianden | 22.50 mi (36.20 km) |
| Luxembourg to Wiltz | 26.08 mi (41.97 km) |
| Luxembourg to Clervaux | 30.60 mi (49.25 km) |
Aleksandrow Kujawski, Włocławski, Poland