Distance from Luxembourg to Aleksandrow Lodzki
The shortest distance (air line) between Luxembourg and Aleksandrow Lodzki is 595.17 mi (957.83 km).
How far is Luxembourg from Aleksandrow Lodzki
Luxembourg is located in Luxembourg, Luxembourg within 49° 36' 42.12" N 6° 7' 54.84" E (49.6117, 6.1319) coordinates. The local time in Luxembourg is 09:44 (12.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 09:44 (12.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 595.17 miles which is equal to 957.83 km.
Luxembourg, Luxembourg, Luxembourg
Related Distances from Luxembourg
Cities | Distance |
---|---|
Luxembourg to Capellen | 6.75 mi (10.87 km) |
Luxembourg to Dudelange | 9.14 mi (14.70 km) |
Luxembourg to Mersch | 9.66 mi (15.55 km) |
Luxembourg to Esch-sur-Alzette | 10.44 mi (16.79 km) |
Luxembourg to Remich | 11.50 mi (18.51 km) |
Luxembourg to Differdange | 12.41 mi (19.98 km) |
Luxembourg to Grevenmacher | 14.65 mi (23.58 km) |
Luxembourg to Redange-sur-Attert | 15.17 mi (24.41 km) |
Luxembourg to Diekirch | 17.75 mi (28.57 km) |
Luxembourg to Echternach | 18.94 mi (30.48 km) |
Luxembourg to Vianden | 22.50 mi (36.20 km) |
Luxembourg to Wiltz | 26.08 mi (41.97 km) |
Luxembourg to Clervaux | 30.60 mi (49.25 km) |
Aleksandrow Lodzki, Łódzki, Poland