Distance from Luxembourg to Auburndale
The shortest distance (air line) between Luxembourg and Auburndale is 4,678.16 mi (7,528.78 km).
How far is Luxembourg from Auburndale
Luxembourg is located in Luxembourg, Luxembourg within 49° 36' 42.12" N 6° 7' 54.84" E (49.6117, 6.1319) coordinates. The local time in Luxembourg is 09:53 (10.03.2025)
Auburndale is located in Florida, United States within 28° 5' 46.68" N -82° 11' 55.68" W (28.0963, -81.8012) coordinates. The local time in Auburndale is 03:53 (10.03.2025)
The calculated flying distance from Auburndale to Auburndale is 4,678.16 miles which is equal to 7,528.78 km.
Luxembourg, Luxembourg, Luxembourg
Related Distances from Luxembourg
| Cities | Distance |
|---|---|
| Luxembourg to Capellen | 6.75 mi (10.87 km) |
| Luxembourg to Dudelange | 9.14 mi (14.70 km) |
| Luxembourg to Mersch | 9.66 mi (15.55 km) |
| Luxembourg to Esch-sur-Alzette | 10.44 mi (16.79 km) |
| Luxembourg to Remich | 11.50 mi (18.51 km) |
| Luxembourg to Differdange | 12.41 mi (19.98 km) |
| Luxembourg to Grevenmacher | 14.65 mi (23.58 km) |
| Luxembourg to Redange-sur-Attert | 15.17 mi (24.41 km) |
| Luxembourg to Diekirch | 17.75 mi (28.57 km) |
| Luxembourg to Echternach | 18.94 mi (30.48 km) |
| Luxembourg to Vianden | 22.50 mi (36.20 km) |
| Luxembourg to Wiltz | 26.08 mi (41.97 km) |
| Luxembourg to Clervaux | 30.60 mi (49.25 km) |
Auburndale, Florida, United States