Distance from Luxembourg to Sannicolau Mare
The shortest distance (air line) between Luxembourg and Sannicolau Mare is 713.53 mi (1,148.31 km).
How far is Luxembourg from Sannicolau Mare
Luxembourg is located in Luxembourg, Luxembourg within 49° 36' 42.12" N 6° 7' 54.84" E (49.6117, 6.1319) coordinates. The local time in Luxembourg is 17:19 (23.02.2025)
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 18:19 (23.02.2025)
The calculated flying distance from Sannicolau Mare to Sannicolau Mare is 713.53 miles which is equal to 1,148.31 km.
Luxembourg, Luxembourg, Luxembourg
Related Distances from Luxembourg
Cities | Distance |
---|---|
Luxembourg to Capellen | 6.75 mi (10.87 km) |
Luxembourg to Dudelange | 9.14 mi (14.70 km) |
Luxembourg to Mersch | 9.66 mi (15.55 km) |
Luxembourg to Esch-sur-Alzette | 10.44 mi (16.79 km) |
Luxembourg to Remich | 11.50 mi (18.51 km) |
Luxembourg to Differdange | 12.41 mi (19.98 km) |
Luxembourg to Grevenmacher | 14.65 mi (23.58 km) |
Luxembourg to Redange-sur-Attert | 15.17 mi (24.41 km) |
Luxembourg to Diekirch | 17.75 mi (28.57 km) |
Luxembourg to Echternach | 18.94 mi (30.48 km) |
Luxembourg to Vianden | 22.50 mi (36.20 km) |
Luxembourg to Wiltz | 26.08 mi (41.97 km) |
Luxembourg to Clervaux | 30.60 mi (49.25 km) |
Sannicolau Mare, Timiş, Romania