Distance from Machesney Park to Aleksandrovac
The shortest distance (air line) between Machesney Park and Aleksandrovac is 5,097.58 mi (8,203.76 km).
How far is Machesney Park from Aleksandrovac
Machesney Park is located in Illinois, United States within 42° 21' 59.76" N -90° 58' 24.24" W (42.3666, -89.0266) coordinates. The local time in Machesney Park is 03:57 (04.10.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 10:57 (04.10.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,097.58 miles which is equal to 8,203.76 km.
Machesney Park, Illinois, United States
Related Distances from Machesney Park
Aleksandrovac, Rasinska oblast, Serbia