Distance from Manhattan Beach to Amberieu-en-Bugey
The shortest distance (air line) between Manhattan Beach and Amberieu-en-Bugey is 5,900.70 mi (9,496.25 km).
How far is Manhattan Beach from Amberieu-en-Bugey
Manhattan Beach is located in California, United States within 33° 53' 21.84" N -119° 36' 11.88" W (33.8894, -118.3967) coordinates. The local time in Manhattan Beach is 08:18 (07.02.2025)
Amberieu-en-Bugey is located in Ain, France within 45° 57' 29.16" N 5° 21' 28.08" E (45.9581, 5.3578) coordinates. The local time in Amberieu-en-Bugey is 17:18 (07.02.2025)
The calculated flying distance from Amberieu-en-Bugey to Amberieu-en-Bugey is 5,900.70 miles which is equal to 9,496.25 km.
Manhattan Beach, California, United States
Related Distances from Manhattan Beach
Amberieu-en-Bugey, Ain, France