Distance from Manhattan Beach to Bad Sassendorf
The shortest distance (air line) between Manhattan Beach and Bad Sassendorf is 5,703.89 mi (9,179.53 km).
How far is Manhattan Beach from Bad Sassendorf
Manhattan Beach is located in California, United States within 33° 53' 21.84" N -119° 36' 11.88" W (33.8894, -118.3967) coordinates. The local time in Manhattan Beach is 11:19 (21.02.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 20:19 (21.02.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 5,703.89 miles which is equal to 9,179.53 km.
Manhattan Beach, California, United States
Related Distances from Manhattan Beach
Bad Sassendorf, Soest, Germany